In an ap a 1 an 20 sn 399

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WebMar 11, 2024 · answered In an Ap, a=1, an=20, sn=399 then find n Advertisement Answer 3 people found it helpful pragyanrana31 Answer: Sn=n/2 (a+l) . . 399=n/2 (1+20) . . 399*2/21=n . . 19*2=n . . N=38 . . Hope this helps you . . Pls mark Brainliest answer! ️ Find Math textbook solutions? Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 … WebIn an AP if a = 1, an = 20 and Sn = 399, then n is _____. CBSE English Medium Class 10. Question Papers 939. Textbook Solutions 33590. MCQ Online Mock Tests 12. Important …

In an A.P. Given a = 3, n = 8, S = 192, find ‘d’. from Mathematics ...

WebFeb 14, 2024 · Solution For (2) In an AP if a=1,an =20, and Sn =399,0 then n is equal a=1an =20Sn =399 t shirts to benefit ukraine

In an AP: (i) given a = 8, an = 62. Sn = 210, find ‘n’ and ‘d’.

WebQuestion If an AP has a = 1, a n = 20 and S n = 399, then find the value of n. Solution Compute the value of n: Formulae: The n th term of an AP is a n = a + n - 1 d and the sum of n terms of a series in an AP is S n = n 2 2 a + ( n - 1) d. Substitute a = 1, a n = 20 in the n th term of an AP formula. WebFeb 27, 2012 · In an AP if a=1, an= 20 and sn =399 then n is a) 13 b) 38 c) 21 d)19 - Maths - Arithmetic Progressions Web20．（本小题满分14分）已知等差数列 an 的公差d 0，它的前n项和为Sn，若 ... 8 Sn . y2. 1的左、右两个顶点分别为A、B．曲21．（本小题满分14分）已知椭圆x 4. 2. 线C是以A、B. P在第一象限且在曲线C上，直线AP与椭圆相交于另一点T．（1）求曲线C的方程； ... philsca student handbook

In an AP, if a =1, an, = 20 and Sn = 399, then find n

WebIn an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) 38 (D) 42 Home Get Answers to all your Questions Home NCERT In an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) 38 (D) 42 #Arithmetic Progressions #NCERT #Maths #Exemplar Maths for Class 10 #1.3 #5.2 #5.3 #5.4 #5.1 #9.2 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 WebÿØÿî AdobedÀ ÿÛ„ ÿÀ € ÿÄØ ! t-shirts to benefit ukraineWebIf in an AP a = 1, t n = 20 and Sn = 399 then n is (a) 19 (b) 21 (c) 38 (d) 42 Report 497 Share Follow Answer peter Reputation: 2.6K University of Lagos, Nigeria 30 July 2024 … t shirts to buy

"WebFeb 22, 2013 · In an A.P. , if a = 1, an= 20 and sn =399, then n is? Share with your friends 1 Follow 0 Jai Prakash, added an answer, on 22/2/13 we know from that formula that, Sn = n/2 (a + an) 399 = n/2 (1 + 20) 399*2 = n (21) n = 798/21 = 38 Therefore n = 38 Was this answer helpful? 3 View Full Answer " - In an ap a 1 an 20 sn 399

In an ap a 1 an 20 sn 399

In an AP: (i) given a = 8, an = 62. Sn = 210, find ‘n’ and ‘d’.

WebIn an AP, if a = 1, an = 20 and Sn = 399, then n is equal to (a) 19 (b) 21 (c) 38 (d) 42 Solution: Question 18: The sum of first five multiples of 3 is (a) 45 (b) 55 (c) 65 (d) 75 Solution: (a) The first five multiples of 3 are 3, 6, 9,12 and 15. Here, first term, a = 3, common difference, d = 6-3 = 3 and number of terms, n = 5 WebSolution: An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous term. The nth term of an AP is. aₙ = a + (n - 1 )d. a = first term. aₙ = nth term. d = common difference. Considering the question, we get the value as,

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WebMar 19, 2024 · In an AP, if a = 1, an = 20 and Sn = 399, then n is equal to A. 19 B. 21 C. 38 D. 42. asked Aug 25, 2024 in Arithmetic Progression by Sima02 (49.6k points) arithmetic progression; class-10; Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. WebIf an AP has a=1, t n=20 and S n=399, then the value of n is A 19 B 32 C 38 D 40 Easy Solution Verified by Toppr Correct option is C) Given, a=1 t n=1+(n−1)d=20 ∴(n−1)d=19 S …

WebSum of n terms of AP is given by: S n = n 2 2 a 1 + n-1 d where a 1 = first term, d = common difference. S 24-4 = 24-4 2 2 × 1 + 24-4-1 13 ∵ d = 13, n = 24, a 1 = 1 S 20 = 20 2 2 + 19 × 13 = 2490. a n-4 = a 1 + n-4-1 d a 24-4 = 1 + 24-4-1 13 ∵ d = 13, n = 24, a 1 = 1 a 20 = 248. Therefore, the ordered pair S n-4, a n-4 is equal to (2490 ... WebHere d = 19 – 20 = (–1) and S n = 200 Hence, the required number of rows are 16 and in the top row there are 5 logs. 224 Views. Answer . The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP. Let the first term and the common difference of the A .P. be a and d ...

WebIn an AP, if a =1, an, = 20 and Sn = 399, then find n. ← Prev Question Next Question → +1 vote . 6.6k views. asked Feb 1, 2024 in Mathematics by Kundan kumar (51.5k points) In an … WebIf an A.P. has a = 1, t n = 20 and s n = 399, then value of n is : A. 20 B. 32 C. 38 D. 40 Answer: Option C Solution (By Examveda Team) S n = 1 2 ( a + l) × n ⇒ 399 = ( 1 + 20) × n 2 ⇒ 399 × 2 = 21 × n ⇒ n = 399 × 2 21 ⇒ n = 19 × 2 ⇒ n = 38 Join The Discussion Related Questions on Progressions How many terms are there in 20, 25, 30 . . . . . . 140?

WebWe can conclude that 10, 20, 30…, 500 is an AP with common difference, d = 10. First term, a = 10. Let the number of terms in this AP = n. Using nth term formula, an = a + (n – 1)d. 500 = 10 + (n – 1)10. 490 = (n – 1)10. n – 1 = 49. n = 50. Sum of an AP, Sn = (n/2) [ a + an], here an is the last term, which is given] = (50/2) ×[10 ...

WebIn an AP if a=1, an =20 and Sn =399, then n is Q. If an AP has a=1, tn=20 and Sn=399, then the value of n is Q. In an AP, if d = - 4 , n = 7 and an = 4, then a is equal to A) 6 B) 7 C) 20 D) … philsca transfereeWebAn arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous … philsca start of classesWebFeb 27, 2012 · In an AP if a=1, an= 20 and sn =399 then n is a) 13 b) 38 c) 21 - Maths - Arithmetic Progressions - 1833845 Meritnation.com Class-10 » Maths Arithmetic … t shirts tk maxxWebBesides giving the explanation of In an A.P. if a=1,An=20 and Sn=399, then find the value of n.?, a detailed solution for In an A.P. if a=1,An=20 and Sn=399, then find the value of n.? … philscat meaningWebAug 25, 2024 · In an AP, if a = 1, an = 20 and Sn = 399, then n is equal to A. 19 B. 21 C. 38 D. 42. ← Prev Question Next Question →. 0 votes. 17.2k views. asked Aug 25, 2024 in … philsca villamor contact numberWebIn an AP if a = 1, a n = 20 and S n = 399, then n is 38. Explanation: ∵ S n = n 2 [ 2 a + ( n - 1) d] 339 = n 2 [ 2 × 1 + ( n - 1) d] 798 = 2 n + n ( n - 1) d ........ (i) And a n = 20 ⇒ a + ( n - 1) d = … philsca tuition fees tourismWebSep 20, 2024 · Given : The first term of an A.P. is 1 and the nth term is 20. If Sn = 399 To find : The value of n ? Solution : The sum of n terms of A.P is given by, Where, a is the first term a=1 l is the nth term l=20 =399 is the sum of n terms Substitute the value in the formula, Therefore, the value of n is 38. #Learn more philsca tuition fee 2021